AM-04.34 · SPACE ACADEMY

AM-04.34 — Cavitation: when liquid begins forming bubbles where the pump needs liquid

Why can a pump malfunction even when the tank still contains plenty of liquid?

📄 Download A4 PDF

1 — Liquid can vaporize locally

If local pressure falls sufficiently relative to the fluid’s thermodynamic state, some liquid can form vapor.

In a pump, vapor pockets may appear and later collapse in higher-pressure regions.

Teaching diagram 1: 1 — Liquid can vaporize locally
1 — Liquid can vaporize locally

2 — Why pump inlet is sensitive

The pump must receive and accelerate fluid. Tank pressure, line losses, vehicle acceleration, and temperature all affect inlet state.

Simply having liquid remaining does not guarantee adequate margin.

Teaching diagram 2: 2 — Why pump inlet is sensitive
2 — Why pump inlet is sensitive

3 — Possible effects

Cavitation can degrade performance and create vibration, noise, and local loads. In demanding turbomachinery it must be considered in design and test.

This lesson remains qualitative and does not provide operating thresholds for a real engine.

Teaching diagram 3: 3 — Possible effects
3 — Possible effects

4 — The reasoning pattern

Compare inlet conditions with fluid properties and preserve margin. If temperature rises, vapor pressure can change; if losses rise, pressure available to the pump can fall.

This is a coupled fluid-thermal-dynamic problem.

Teaching diagram 4: 4 — The reasoning pattern
4 — The reasoning pattern

Three complete examples: change one assumption to understand

Before each calculation, identify where every number comes from and whether it is measured, conventional, assumed, or calculated.

Three numerical examples in the course
Three compared cases

Example A — conceptual margin

Inlet pressure 300 kPa, reference vapor value 200 kPa: simple margin=100 kPa.

🎓 TEACHING ASSUMPTION, not an engine criterion.

Example B — additional losses

If 60 kPa extra loss lowers inlet to 240 kPa, simple margin=40 kPa.

Margin falls sharply without changing remaining liquid quantity.

Example C — higher vapor reference

Inlet 300 kPa but vapor reference 260 kPa: margin=40 kPa.

Fluid temperature/property can change the problem at the same inlet pressure.

Inverse calculation

If a conceptual exercise margin is 80 kPa and vapor reference is 200 kPa, inlet pressure would need at least 280 kPa in this simplified model.

Common trap and result check

Trap: turning the lesson’s simple pressure difference into a sizing rule. Real criteria use specific definitions, properties, and tests.

In a real engine system, a conceptual result must later be checked against fluid properties, margins, tests, and qualification.

Exercises and answers

Function

Explain the function of each block without jargon.

Answer: A correct answer says what enters, what leaves, and why the block is needed.

Sensitivity

Halve one assumption and predict the consequence.

Answer: Explain the direction of change before calculating.

Limit

Name one reason the teaching model is insufficient for a real engine.

Answer: Fluid properties, transient dynamics, cavitation, heat, materials, stability, manufacturing, or control.

Primary and educational sources